Cleaning HTML in Google+ content by stripping out HTML tags and converting HTML entities back to plain-text representations¶
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from bs4 import BeautifulSoup # pip install beautifulsoup4
def cleanHtml(html):
if html == "": return ""
return BeautifulSoup(html, 'html5lib').get_text()
txt = "Don't forget about HTML entities and <strong>markup</strong> when "+\
"mining text!<br />"
print(cleanHtml(txt))
Sample data structures used in illustrations for the rest of this chapter¶
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corpus = {
'a' : "Mr. Green killed Colonel Mustard in the study with the candlestick. \
Mr. Green is not a very nice fellow.",
'b' : "Professor Plum has a green plant in his study.",
'c' : "Miss Scarlett watered Professor Plum's green plant while he was away \
from his office last week."
}
terms = {
'a' : [ i.lower() for i in corpus['a'].split() ],
'b' : [ i.lower() for i in corpus['b'].split() ],
'c' : [ i.lower() for i in corpus['c'].split() ]
}
Running TF-IDF on sample data¶
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from math import log
# Enter in a query term from the corpus variable
QUERY_TERMS = ['mr.', 'green']
def tf(term, doc, normalize=True):
doc = doc.lower().split()
if normalize:
return doc.count(term.lower()) / float(len(doc))
else:
return doc.count(term.lower()) / 1.0
def idf(term, corpus):
num_texts_with_term = len([True for text in corpus if term.lower()
in text.lower().split()])
# tf-idf calc involves multiplying against a tf value less than 0, so it's
# necessary to return a value greater than 1 for consistent scoring.
# (Multiplying two values less than 1 returns a value less than each of
# them.)
try:
return 1.0 + log(float(len(corpus)) / num_texts_with_term)
except ZeroDivisionError:
return 1.0
def tf_idf(term, doc, corpus):
return tf(term, doc) * idf(term, corpus)
corpus = \
{'a': 'Mr. Green killed Colonel Mustard in the study with the candlestick. \
Mr. Green is not a very nice fellow.',
'b': 'Professor Plum has a green plant in his study.',
'c': "Miss Scarlett watered Professor Plum's green plant while he was away \
from his office last week."}
for (k, v) in sorted(corpus.items()):
print(k, ':', v)
print()
# Score queries by calculating cumulative tf_idf score for each term in query
query_scores = {'a': 0, 'b': 0, 'c': 0}
for term in [t.lower() for t in QUERY_TERMS]:
for doc in sorted(corpus):
print('TF({0}): {1}'.format(doc, term), tf(term, corpus[doc]))
print('IDF: {0}'.format(term), idf(term, corpus.values()))
print()
for doc in sorted(corpus):
score = tf_idf(term, corpus[doc], corpus.values())
print('TF-IDF({0}): {1}'.format(doc, term), score)
query_scores[doc] += score
print()
print("Overall TF-IDF scores for query '{0}'".format(' '.join(QUERY_TERMS)))
for (doc, score) in sorted(query_scores.items()):
print(doc, score)
Exploring text data with NLTK¶
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# Explore some of NLTK's functionality by exploring the data.
# Here are some suggestions for an interactive interpreter session.
import json
import nltk
# Download ancillary nltk packages if not already installed
nltk.download('stopwords')
# Load in human language data from wherever you've saved it
DATA = 'resources/ch05-textfiles/ch05-timoreilly.json'
data = json.loads(open(DATA).read())
# Combine titles and post content
all_content = " ".join([ i['title'] + " " + i['content'] for i in data ])
# Approximate bytes of text
print(len(all_content))
tokens = all_content.split()
text = nltk.Text(tokens)
# Examples of the appearance of the word "open"
text.concordance("open")
# Frequent collocations in the text (usually meaningful phrases)
text.collocations()
# Frequency analysis for words of interest
fdist = text.vocab()
print(fdist["open"])
print(fdist["source"])
print(fdist["web"])
print(fdist["2.0"])
# Number of words in the text
print('Number of tokens:', len(tokens))
# Number of unique words in the text
print('Number of unique words:', len(fdist.keys()))
# Common words that aren't stopwords
print('Common words that aren\'t stopwords')
print([w for w in list(fdist.keys())[:100]
if w.lower() not in nltk.corpus.stopwords.words('english')])
# Long words that aren't URLs
print('Long words that aren\'t URLs')
print([w for w in fdist.keys() if len(w) > 15 and 'http' not in w])
# Number of URLs
print('Number of URLs: ',len([w for w in fdist.keys() if 'http' in w]))
# Top 10 Most Common Words
print('Top 10 Most Common Words')
print(fdist.most_common(10))
Querying text data with TF-IDF¶
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import json
import nltk
# Provide your own query terms here
QUERY_TERMS = ['Government']
# Load in human language data from wherever you've saved it
DATA = 'resources/ch05-textfiles/ch05-timoreilly.json'
data = json.loads(open(DATA).read())
activities = [post['content'].lower().split()
for post in data
if post['content'] != ""]
# TextCollection provides tf, idf, and tf_idf abstractions so
# that we don't have to maintain/compute them ourselves
tc = nltk.TextCollection(activities)
relevant_activities = []
for idx in range(len(activities)):
score = 0
for term in [t.lower() for t in QUERY_TERMS]:
score += tc.tf_idf(term, activities[idx])
if score > 0:
relevant_activities.append({'score': score, 'title': data[idx]['title']})
# Sort by score and display results
relevant_activities = sorted(relevant_activities,
key=lambda p: p['score'], reverse=True)
for activity in relevant_activities:
print('Title: {0}'.format(activity['title']))
print('Score: {0}'.format(activity['score']))
print()
Finding similar documents using cosine similarity¶
The dot product of two vectors A and B can be thought of as a projection of one vector into the other.
By measuring how much of A is in the same direction as B, we get a measure of how similar A is to B. The idea behind the following exercise is to create vectors for each document in our corpus consisting of the TF-IDF scores of the terms in those documents:
v_1 = [ tf_idf(term_1, doc_1), tf_idf(term_2, doc_1), ..., tf_idf(term_n, doc_1) ]
v_2 = [ tf_idf(term_1, doc_2), tf_idf(term_2, doc_2), ..., tf_idf(term_n, doc_2) ]The dot product of these vectors:
$\mathbf{v_1} \cdot \mathbf{v_2} = |\mathbf{v_1}||\mathbf{v_2}|\cos(\theta)$.
Now you see where the cosine comes in. The "cosine distance" between $\mathbf{v1}$ and $\mathbf{v2}$ is then given by
$$ d = 1 - \frac{\mathbf{v_1} \cdot \mathbf{v_2}}{|\mathbf{v_1}||\mathbf{v_2}|} $$In [ ]:
import json
import nltk
import nltk.cluster
# Load in human language data from wherever you've saved it
DATA = 'resources/ch05-textfiles/ch05-timoreilly.json'
data = json.loads(open(DATA).read())
all_posts = [ (i['title'] + " " + i['content']).lower().split() for i in data ]
# Provides tf, idf, and tf_idf abstractions for scoring
tc = nltk.TextCollection(all_posts)
# Compute a term-document matrix such that td_matrix[doc_title][term]
# returns a tf-idf score for the term in the document
td_matrix = {}
for idx in range(len(all_posts)):
post = all_posts[idx]
fdist = nltk.FreqDist(post)
doc_title = data[idx]['title'].replace('\n', '')
td_matrix[doc_title] = {}
for term in fdist.keys():
td_matrix[doc_title][term] = tc.tf_idf(term, post)
# Build vectors such that term scores are in the same positions...
distances = {}
for title1 in td_matrix.keys():
distances[title1] = {}
(min_dist, most_similar) = (1.0, ('', ''))
for title2 in td_matrix.keys():
# Take care not to mutate the original data structures
# since we're in a loop and need the originals multiple times
terms1 = td_matrix[title1].copy()
terms2 = td_matrix[title2].copy()
# Fill in "gaps" in each map so vectors of the same length can be computed
for term1 in terms1:
if term1 not in terms2:
terms2[term1] = 0
for term2 in terms2:
if term2 not in terms1:
terms1[term2] = 0
# Create vectors from term maps
v1 = [score for (term, score) in sorted(terms1.items())]
v2 = [score for (term, score) in sorted(terms2.items())]
# Compute similarity amongst documents
distances[title1][title2] = nltk.cluster.util.cosine_distance(v1, v2)
if title1 == title2:
#print distances[title1][title2]
continue
if distances[title1][title2] < min_dist:
(min_dist, most_similar) = (distances[title1][title2], title2)
print(u'Most similar (score: {})\n{}\n{}\n'.format(1-min_dist, title1,
most_similar))
Generating a figure to visually display the cosine similarity between documents¶
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import numpy as np
import matplotlib.pyplot as plt # pip install matplotlib
%matplotlib inline
max_articles = 15
# Get the titles - the keys to the 'distances' dict
keys = list(distances.keys())
# Extract the article titles
titles = [l[:40].replace('\n',' ')+'...' for l in list(distances.keys())]
n_articles = len(titles) if len(titles) < max_articles else max_articles
# Initialize the matrix of appropriate size to store similarity scores
similarity_matrix = np.zeros((n_articles, n_articles))
# Loop over the cells in the matrix
for i in range(n_articles):
for j in range(n_articles):
# Retrieve the cosine distance between articles i and j
d = distances[keys[i]][keys[j]]
# Store the 'similarity' between articles i and j, defined as 1.0 - distance
similarity_matrix[i, j] = 1.0 - d
# Create a figure and axes
fig = plt.figure(figsize=(8,8), dpi=300)
ax = fig.add_subplot(111)
# Visualize the matrix with colored squares indicating similarity
ax.matshow(similarity_matrix, cmap='Greys', vmin = 0.0, vmax = 0.2)
# Set regular ticks, one for each article in the collection
ax.set_xticks(range(n_articles))
ax.set_yticks(range(n_articles))
# Set the tick labels as the article titles
ax.set_xticklabels(titles)
ax.set_yticklabels(titles)
# Rotate the labels on the x-axis by 90 degrees
plt.xticks(rotation=90);
Using NLTK to compute bigrams and collocations for a sentence¶
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import nltk
sentence = "Mr. Green killed Colonel Mustard in the study with the " + \
"candlestick. Mr. Green is not a very nice fellow."
print([bg for bg in nltk.ngrams(sentence.split(), 2)])
txt = nltk.Text(sentence.split())
txt.collocations()
Using NLTK to compute collocations in a similar manner to the nltk.Text.collocations demo functionality¶
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import json
import nltk
from nltk.metrics import association
# Load in human language data from wherever you've saved it
DATA = 'resources/ch05-textfiles/ch05-timoreilly.json'
data = json.loads(open(DATA).read())
# Number of collocations to find
N = 25
all_tokens = [token for post in data for token in post['content'].lower().split()]
finder = nltk.BigramCollocationFinder.from_words(all_tokens)
finder.apply_freq_filter(2)
finder.apply_word_filter(lambda w: w in nltk.corpus.stopwords.words('english'))
scorer = association.BigramAssocMeasures.jaccard
collocations = finder.nbest(scorer, N)
for collocation in collocations:
c = ' '.join(collocation)
print(c)
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